Answer:
(B)[tex]4\sqrt{37}[/tex]
Step-by-step explanation:
First, we determine the height of the triangle which we label as y.
Using Pythagoras Theorem.
[tex]25^2=7^2+y^2\\y^2=25^2-7^2\\y^2=576\\y=\sqrt{576}\\y=24[/tex]
In the smaller right triangle with hypotenuse, x
Base = 7-3 =4 Units
Height, y= 24 Units
Therefore, applying Pythagoras Theorem.:
[tex]x^2=24^2+4^2\\x^2=592\\x=\sqrt{592}\\ x=4\sqrt{37}[/tex]
